Question of the Day #264 (24/5/10)

[Kazza]

Using all of the following numbers once only, work out the following sum:

1 2 3 4 5 6

_ _ x _ = _ _ _


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[skooter65]

PM Sent. Happy Monday!

 

[chaskell27]

Not sure if I can play today or not but PM sent either way

 

[GConn]

Pm on the way

 

[Kazza]

Not sure if I can play today or not but PM sent either way

You are eligible ONLY because I missed a day (I had no QOTD on Friday).

Otherwise, still applies that you win a game, miss a game

 

[1adam1212]

PM sent!!!!!!!!!!!!!!

 

[Mancolt]

PM Sent...

 

[Shinleung]

pm sent

this one is hard.
I juz got it by trail and error, hope its right.

I am interested if there is a way of doing this.

 

[Mancolt]

I started by trial and error, but then I came up with a methodology that sped up the process. I'll post what I did tomorrow for you but I am also curious if there is an actual way to mathematically solve this.

 

[Wh0M3]

pm sent. :thumbup:

 

[SirIsaac]

PM sent...

 

[bertmoog]

PM sent, thank you!

 

[Dr.Moby]

PM on the way. Thanks!
DrM

 

[CHEMIKER]

Boosh! :Sport:

 

[BusyWeb]

Thanks for the easier one... ha ha ha
PM sent..

 

[westgoingzax]

I'm curious how to solve this without 'guess and check' also!

 

[Kazza]

Using all of the following numbers once only, work out the following sum:

1 2 3 4 5 6

_ _ x _ = _ _ _

The answer is
54 x 3 = 162
I don't know a quick way to work this out, for me it's trial and error!

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Skooter65; Chaskell27; GConn

REP WINNERS:

1adam1212; Mancolt; Wh0M3; SirIsaac; Bertmoog; Dr.Moby; Chemiker; Busyweb; Westgoingzax


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[Mancolt]

Here's what I did to solve it, though I'd still like a math wiz to tell me how to do it without trial and error. I just created an Excel table with all the possible multiplication combinations.

You can remove all of the numbers from the 1 column. You can remove any numbers that contain duplicate numbers. You can remove any numbers that have a "0", "7", "8", or "9". Once you establish the criteria, you can remove numbers pretty quickly and get it narrowed down. I found this way to be much quicker for me than just guessing and checking random numbers hoping to get it.

 

[GConn]

This is similar to the way I used too. I don't really think there is another mathematical way to calculate the answer.

 

[westgoingzax]

Here's what I did to solve it

That's exactly what I did too.